ydx+(x+2xy^2-2y)=0

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Solution for ydx+(x+2xy^2-2y)=0 equation:


Simplifying
ydx + (x + 2xy2 + -2y) = 0

Remove parenthesis around (x + 2xy2 + -2y)
dxy + x + 2xy2 + -2y = 0

Solving
dxy + x + 2xy2 + -2y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1x' to each side of the equation.
dxy + x + 2xy2 + -1x + -2y = 0 + -1x

Reorder the terms:
dxy + x + -1x + 2xy2 + -2y = 0 + -1x

Combine like terms: x + -1x = 0
dxy + 0 + 2xy2 + -2y = 0 + -1x
dxy + 2xy2 + -2y = 0 + -1x
Remove the zero:
dxy + 2xy2 + -2y = -1x

Add '-2xy2' to each side of the equation.
dxy + 2xy2 + -2xy2 + -2y = -1x + -2xy2

Combine like terms: 2xy2 + -2xy2 = 0
dxy + 0 + -2y = -1x + -2xy2
dxy + -2y = -1x + -2xy2

Add '2y' to each side of the equation.
dxy + -2y + 2y = -1x + -2xy2 + 2y

Combine like terms: -2y + 2y = 0
dxy + 0 = -1x + -2xy2 + 2y
dxy = -1x + -2xy2 + 2y

Divide each side by 'xy'.
d = -1y-1 + -2y + 2x-1

Simplifying
d = -1y-1 + -2y + 2x-1

Reorder the terms:
d = 2x-1 + -1y-1 + -2y

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